Integrand size = 15, antiderivative size = 41 \[ \int \frac {\tan (x)}{\sqrt {a+b \tan ^4(x)}} \, dx=-\frac {\text {arctanh}\left (\frac {a-b \tan ^2(x)}{\sqrt {a+b} \sqrt {a+b \tan ^4(x)}}\right )}{2 \sqrt {a+b}} \]
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Time = 0.09 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.267, Rules used = {3751, 1262, 739, 212} \[ \int \frac {\tan (x)}{\sqrt {a+b \tan ^4(x)}} \, dx=-\frac {\text {arctanh}\left (\frac {a-b \tan ^2(x)}{\sqrt {a+b} \sqrt {a+b \tan ^4(x)}}\right )}{2 \sqrt {a+b}} \]
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Rule 212
Rule 739
Rule 1262
Rule 3751
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int \frac {x}{\left (1+x^2\right ) \sqrt {a+b x^4}} \, dx,x,\tan (x)\right ) \\ & = \frac {1}{2} \text {Subst}\left (\int \frac {1}{(1+x) \sqrt {a+b x^2}} \, dx,x,\tan ^2(x)\right ) \\ & = -\left (\frac {1}{2} \text {Subst}\left (\int \frac {1}{a+b-x^2} \, dx,x,\frac {a-b \tan ^2(x)}{\sqrt {a+b \tan ^4(x)}}\right )\right ) \\ & = -\frac {\text {arctanh}\left (\frac {a-b \tan ^2(x)}{\sqrt {a+b} \sqrt {a+b \tan ^4(x)}}\right )}{2 \sqrt {a+b}} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.00 \[ \int \frac {\tan (x)}{\sqrt {a+b \tan ^4(x)}} \, dx=-\frac {\text {arctanh}\left (\frac {a-b \tan ^2(x)}{\sqrt {a+b} \sqrt {a+b \tan ^4(x)}}\right )}{2 \sqrt {a+b}} \]
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Time = 0.19 (sec) , antiderivative size = 65, normalized size of antiderivative = 1.59
method | result | size |
derivativedivides | \(-\frac {\ln \left (\frac {2 a +2 b -2 b \left (1+\tan \left (x \right )^{2}\right )+2 \sqrt {a +b}\, \sqrt {b \left (1+\tan \left (x \right )^{2}\right )^{2}-2 b \left (1+\tan \left (x \right )^{2}\right )+a +b}}{1+\tan \left (x \right )^{2}}\right )}{2 \sqrt {a +b}}\) | \(65\) |
default | \(-\frac {\ln \left (\frac {2 a +2 b -2 b \left (1+\tan \left (x \right )^{2}\right )+2 \sqrt {a +b}\, \sqrt {b \left (1+\tan \left (x \right )^{2}\right )^{2}-2 b \left (1+\tan \left (x \right )^{2}\right )+a +b}}{1+\tan \left (x \right )^{2}}\right )}{2 \sqrt {a +b}}\) | \(65\) |
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Time = 0.36 (sec) , antiderivative size = 150, normalized size of antiderivative = 3.66 \[ \int \frac {\tan (x)}{\sqrt {a+b \tan ^4(x)}} \, dx=\left [\frac {\log \left (\frac {{\left (a b + 2 \, b^{2}\right )} \tan \left (x\right )^{4} - 2 \, a b \tan \left (x\right )^{2} + 2 \, \sqrt {b \tan \left (x\right )^{4} + a} {\left (b \tan \left (x\right )^{2} - a\right )} \sqrt {a + b} + 2 \, a^{2} + a b}{\tan \left (x\right )^{4} + 2 \, \tan \left (x\right )^{2} + 1}\right )}{4 \, \sqrt {a + b}}, -\frac {\sqrt {-a - b} \arctan \left (\frac {\sqrt {b \tan \left (x\right )^{4} + a} {\left (b \tan \left (x\right )^{2} - a\right )} \sqrt {-a - b}}{{\left (a b + b^{2}\right )} \tan \left (x\right )^{4} + a^{2} + a b}\right )}{2 \, {\left (a + b\right )}}\right ] \]
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\[ \int \frac {\tan (x)}{\sqrt {a+b \tan ^4(x)}} \, dx=\int \frac {\tan {\left (x \right )}}{\sqrt {a + b \tan ^{4}{\left (x \right )}}}\, dx \]
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\[ \int \frac {\tan (x)}{\sqrt {a+b \tan ^4(x)}} \, dx=\int { \frac {\tan \left (x\right )}{\sqrt {b \tan \left (x\right )^{4} + a}} \,d x } \]
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Time = 0.27 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.12 \[ \int \frac {\tan (x)}{\sqrt {a+b \tan ^4(x)}} \, dx=\frac {\arctan \left (-\frac {\sqrt {b} \tan \left (x\right )^{2} - \sqrt {b \tan \left (x\right )^{4} + a} + \sqrt {b}}{\sqrt {-a - b}}\right )}{\sqrt {-a - b}} \]
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Timed out. \[ \int \frac {\tan (x)}{\sqrt {a+b \tan ^4(x)}} \, dx=\int \frac {\mathrm {tan}\left (x\right )}{\sqrt {b\,{\mathrm {tan}\left (x\right )}^4+a}} \,d x \]
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